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The FordGenuine 7L1Z-3C247-A Door Lock Actuator Assembly is an OEM part designed for Ford F150 and Expedition models, ensuring a perfect fit and reliable performance. With its compact dimensions and lightweight design, this actuator is engineered for durability and ease of installation, making it the ideal choice for enhancing your vehicle's functionality.
| Manufacturer | Ford |
| Brand | Ford |
| Model | 7L1Z-3C247-A |
| Product Dimensions | 20.32 x 20.32 x 20.32 cm; 408.23 g |
| Item model number | 7L1Z-3C247-A |
| Exterior | Polished |
| Manufacturer Part Number | 7L1Z-3C247-A |
| OEM Part Number | 0, 7L1Z-3C247-A |
| Item Weight | 408 g |
J**E
Perfect fit 2007 f150 lariat 4x4
Factory product, easy installation and work great, highly recommended
G**L
Perfect fit, best price.
Some people complain that product is junk but I will disagree. I installed both sides on my 2014 F150 and I’m not a mechanic (tricky but doable) saved a lot of money and the are working perfectly even after 2 yrs
G**R
fit was perfect
Product fit perfect and hope it last for as long as the original one in new in 2008
M**Y
Yes, it's a Ford IWE
It's strangely listed as "Genuine Ford 7L1Z-3C247-A Door Lock Actuator Assembly." But, have no fear; it's truly an IWE.Ford part in Ford packaging. It should last as long as the IWE that's on your F-150 now (unfortunately).I have gotten pretty good at changing these quickly. Current IWE replacement count on my 196,000 mile 2004 F-150 is: LF 3, RF 4.Don't worry about removing the steering tie rod. Just detach the upper ball joint, caliper, and driveshaft nut, then also remove the 3 IWE bolts. Leave the IWE on the driveshaft, and it will be juuuuust enough to swing the spindle out of the way of the driveshaft. Clean well and re-grease accordingly.
J**Y
Works great
Dealer asks for $950 to replace 2 IWE, I did it myself with this part for only $150
Trustpilot
1 month ago
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